sql查询列转行
❶ sql 列转行
CREATE TABLE T1(A NUMBER,
b NUMBER,
c NUMBER,
d NUMBER,
e NUMBER);
insert into t1 values(1,2,3,4,5);
select * from t1;
select decode(A,1,'A',null) KEY ,decode(A,1,1,null) VALUE
from t1
union all
select decode(B,2,'B',null),decode(B,2,2,null)
from t1
union all
select decode(C,3,'C',null),decode(C,3,3,null)
from t1
union all
select decode(D,4,'D',null),decode(D,4,4,null)
from t1
union all
select decode(E,5,'E',null),decode(E,5,5,null)
from t1;
❷ sql 列转行
先建一张转换后的表
create table changed
(
id number,
key varchar2(10),
val varchar2(10)
)
然后执行下面的插入语句
insert all
into changed(id,key,val) values(id,'a',a)
into changed(id,key,val) values(id,'b',b)
into changed(id,key,val) values(id,'c',c)
into changed(id,key,val) values(id,'d',d)
into changed(id,key,val) values(id,'e',e)
select id,a,b,c,d,e from change;
如果需要继续添加,就模仿上面的格式写好了,最后别忘记commit;
❸ sql语句列转行
--方法对了,其实超级容易,下面给你一个例子,实际的请自己改写一下,以下代码可以在sql server中执行,返回的就是你要的结果
--将你的数据存入表
declare @a table(ii varchar(10),jj varchar(10))
insert into @a values('c_003','套餐A')
insert into @a values('c_004','49')
insert into @a values('c_005','300')
insert into @a values('c_003','套餐B')
insert into @a values('c_004','59')
insert into @a values('c_005','700')
--检索一下,看是否是正确的
select * from @a
--将数据行做成列表
declare @b table(c_003 varchar(10),c_004 varchar(10),c_005 varchar(10))
--定义游标完成数据转换
declare cur_a_b cursor for select ii,jj from @a
declare @i int --定义步长,方便以3为不同的步长
set @i=0
declare @ii varchar(10)
declare @jj varchar(10)
--临时的c_003变量
declare @fn varchar(20)
--打开游标
open cur_a_b
fetch next from cur_a_b into @ii,@jj
while @@fetch_status = 0
begin
if @i % 3 = 0
begin
set @fn = @jj
insert into @b(c_003) values(@fn)
end
if @i % 3 = 1 update @b set c_004=@jj where c_003=@fn
if @i % 3 = 2 update @b set c_005=@jj where c_003=@fn
set @i = @i + 1
fetch next from cur_a_b into @ii,@jj
end
close cur_a_b
deallocate cur_a_b
--最终结果
select * from @b
--呵呵,写了这么多也不容易,加点分吧
❹ SQL语句 列转行
-- ========================= PIVOT 行列转置 ===========================
-- 1、【行列转置PIVOT】
declare @Score table(StuNo varchar(10), StuName varchar(50), CourseName varchar(50), Score int)
insert into @Score
select '1', 'Tom', 'Math', 80 union all
select '1', 'Tom', 'English', 82 union all
select '1', 'Tom', 'Geography', 84 union all
select '2', 'Jone', 'Math', 79 union all
select '2', 'Jone', 'English', 88 union all
select '2', 'Jone', 'Geography',86
select * from @Score
SELECT StuNo, StuName, Math, English, [Geography]
FROM @Score PIVOT (MAX(Score) FOR CourseName in (Math, English, [Geography]) ) AS ScoreList
ORDER BY StuNo
-- 2、【列行转置UNPIVOT】
declare @ScoreList table(StuNo varchar(10), StuName varchar(50), Math int, English int, [Geography] int)
insert into @ScoreList
select '1', 'Tom', 80, 82, 84 union all
select '2', 'Jone', 79, 88, 86
select * from @ScoreList
SELECT StuNo, StuName, CourseName, Score
FROM @ScoreList UNPIVOT (Score FOR CourseName in (Math, English, [Geography]) ) AS ScorePvtTable
ORDER BY StuNo
❺ sql语句列转行
我整理的行转列的问题:
--创建tb表
createtabletb(姓名varchar(10),课程varchar(10),分数int)
insertintotbvalues('张三','语文',74)
insertintotbvalues('张三','数学',83)
insertintotbvalues('张三','物理',93)
insertintotbvalues('李四','语文',74)
insertintotbvalues('李四','数学',84)
insertintotbvalues('李四','物理',94)
go
select*Fromtb
--SQLSERVER2000静态行转列
select姓名as姓名,
max(case课程when'语文'then分数elsenullend)语文,
max(case课程when'数学'then分数elsenullend)数学,
max(case课程when'物理'then分数elsenullend)物理
fromtb
groupby姓名
--SQLSERVER2000动态SQL,指课程不止语文、数学、物理这三门课程。(以下同)
declare@sqlvarchar(8000)
set@sql='select姓名'
select@sql=@sql+',max(case课程when'''+课程+'''then分数else0end)['+课程+']'
from(selectdistinct课程fromtb)asa
set@sql=@sql+'fromtbgroupby姓名'
exec(@sql)
--SQLSERVER2005静态SQL。
select*from(select*fromtb)apivot(max(分数)for课程in(语文,数学,物理))b
--SQLSERVER2005动态SQL。
declare@sqlvarchar(8000)
select@sql=isnull(@sql+'],[','')+课程fromtbgroupby课程
set@sql='['+@sql+']'
exec('select*from(select*fromtb)apivot(max(分数)for课程in('+@sql+'))b')
希望对你的学习有帮助。
❻ sql语句列转行
主要应用case语句来解决行转列的问题
行转列问题主要分为两类
1)简单的行转列问题:
示例表:
id
sid
course
result
1
2005001
语文
80.0
2
2005001
数学
90.0
3
2005001
英语
80.0
4
2005002
语文
56.0
5
2005002
数学
69.0
6
2005002
英语
89.0
执行
select
sid,语文=isnull(sum(case
course
when
'语文'
then
result
end),0),
数学=isnull(sum(case
course
when
'数学'
then
result
end),0),
英语=isnull(sum(case
course
when
'英语'
then
result
end),0)
from
result
group
by
sid
order
by
sid
得出结果
sid
语文
数学
英语
2005001
80.0
90.0
80.0
2005002
56.0
69.0
89.0