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javaxmltojson

发布时间: 2023-01-11 06:36:22

java实现复杂的 xml 转化为 JSON

提供一种方案:xml通过jaxb转换成java对象,
然后java对象再转换为json, 都有现成的框架。

Ⅱ 在java中怎么把xml文件转换成json格式

在java中把xml文件转换成json格式
1、前提需要jar包:
json-lib-2.4-jdk15.jar 和 xom-1.2.5.jar ,maven 仓库:
net.sf.json-lib
json-lib
2.4
jdk15

xom
xom
1.2.5

2、代码部分:
public static JSON xmlToJson(String xml) {
XMLSerializer xmlSerializer = new XMLSerializer();
if(xml!=null && !”“.equals(xml)){
xml = xml.replaceAll(“\r|\n”, “”);
JSON json = xmlSerializer.read(xml);
return json;
}else{
return null;
}

}
public static void main(String[] args) {
String xmlStr = "<parent><id>01</id<name>marry</name</parent>";
JSON json = xmlToJson(xmlStr);
System.out.println(json.toString());

}
3、结果:
{“id”:”01”,”name”:”marry”}

Ⅲ JAVA能把下面的 xml 转化为JSON

<p>package com.shine.framework.core.util;</p>
import java.io.ByteArrayOutputStream;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map;

import net.sf.json.JSON;
import net.sf.json.JSONSerializer;
import net.sf.json.xml.XMLSerializer;

import org.dom4j.Document;
import org.dom4j.DocumentHelper;
import org.dom4j.Element;
import org.dom4j.io.OutputFormat;
import org.dom4j.io.XMLWriter;

/**
* common xml conver utility
*
* @author [email protected]
* @version Framework 2010.10.26
* @url http://blog.csdn.net/arjick/article/details/6251777
*/
public class XmlConverUtil {
/**
* map to xml xml <node><key label="key1">value1</key><key
* label="key2">value2</key>......</node>
*
* @param map
* @return
*/
public static String maptoXml(Map map) {
Document document = DocumentHelper.createDocument();
Element nodeElement = document.addElement("node");
for (Object obj : map.keySet()) {
Element keyElement = nodeElement.addElement("key");
keyElement.addAttribute("label", String.valueOf(obj));
keyElement.setText(String.valueOf(map.get(obj)));
}
return doc2String(document);
}

/**
* list to xml xml <nodes><node><key label="key1">value1</key><key
* label="key2">value2</key>......</node><node><key
* label="key1">value1</key><key
* label="key2">value2</key>......</node></nodes>
*
* @param list
* @return
*/
public static String listtoXml(List list) throws Exception {
Document document = DocumentHelper.createDocument();
Element nodesElement = document.addElement("nodes");
int i = 0;
for (Object o : list) {
Element nodeElement = nodesElement.addElement("node");
if (o instanceof Map) {
for (Object obj : ((Map) o).keySet()) {
Element keyElement = nodeElement.addElement("key");
keyElement.addAttribute("label", String.valueOf(obj));
keyElement.setText(String.valueOf(((Map) o).get(obj)));
}
} else {
Element keyElement = nodeElement.addElement("key");
keyElement.addAttribute("label", String.valueOf(i));
keyElement.setText(String.valueOf(o));
}
i++;
}
return doc2String(document);
}

/**
* json to xml {"node":{"key":{"@label":"key1","#text":"value1"}}} conver
* <o><node class="object"><key class="object"
* label="key1">value1</key></node></o>
*
* @param json
* @return
*/
public static String jsontoXml(String json) {
try {
XMLSerializer serializer = new XMLSerializer();
JSON jsonObject = JSONSerializer.toJSON(json);
return serializer.write(jsonObject);
} catch (Exception e) {
e.printStackTrace();
}
return null;
}

/**
* xml to map xml <node><key label="key1">value1</key><key
* label="key2">value2</key>......</node>
*
* @param xml
* @return
*/
public static Map xmltoMap(String xml) {
try {
Map map = new HashMap();
Document document = DocumentHelper.parseText(xml);
Element nodeElement = document.getRootElement();
List node = nodeElement.elements();
for (Iterator it = node.iterator(); it.hasNext();) {
Element elm = (Element) it.next();
map.put(elm.attributeValue("label"), elm.getText());
elm = null;
}
node = null;
nodeElement = null;
document = null;
return map;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}

/**
* xml to list xml <nodes><node><key label="key1">value1</key><key
* label="key2">value2</key>......</node><node><key
* label="key1">value1</key><key
* label="key2">value2</key>......</node></nodes>
*
* @param xml
* @return
*/
public static List xmltoList(String xml) {
try {
List<Map> list = new ArrayList<Map>();
Document document = DocumentHelper.parseText(xml);
Element nodesElement = document.getRootElement();
List nodes = nodesElement.elements();
for (Iterator its = nodes.iterator(); its.hasNext();) {
Element nodeElement = (Element) its.next();
Map map = xmltoMap(nodeElement.asXML());
list.add(map);
map = null;
}
nodes = null;
nodesElement = null;
document = null;
return list;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}

/**
* xml to json <node><key label="key1">value1</key></node> 转化为
* {"key":{"@label":"key1","#text":"value1"}}
*
* @param xml
* @return
*/
public static String xmltoJson(String xml) {
XMLSerializer xmlSerializer = new XMLSerializer();
return xmlSerializer.read(xml).toString();
}

/**
*
* @param document
* @return
*/
public static String doc2String(Document document) {
String s = "";
try {
// 使用输出流来进行转化
ByteArrayOutputStream out = new ByteArrayOutputStream();
// 使用UTF-8编码
OutputFormat format = new OutputFormat(" ", true, "UTF-8");
XMLWriter writer = new XMLWriter(out, format);
writer.write(document);
s = out.toString("UTF-8");
} catch (Exception ex) {
ex.printStackTrace();
}
return s;
}
}需要的jar
需要json-lib-2.1-jdk15.jar和xom-1.2.5.jar,maven pom.xml如下:

Ⅳ java 用XMLSerializer处理xml转json时,xml节点的属性在转为json后,属性上为有@符号,怎么处理掉@。

@要用replace替换成-减号符,这样在json字符串中能代表属性

Ⅳ javascript 将xml转换为json对象

代码如下:


//ChangesXMLtoJSON
functionxmlToJson(xml){
//Createthereturnobject
varobj={};
if(xml.nodeType==1){//element
//doattributes
if(xml.attributes.length>0){
obj["@attributes"]={};
for(varj=0;j<xml.attributes.length;j++){
varattribute=xml.attributes.item(j);
obj["@attributes"][attribute.nodeName]=attribute.nodeValue;
}
}
}elseif(xml.nodeType==3){//text
obj=xml.nodeValue;
}
//dochildren
if(xml.hasChildNodes()){
for(vari=0;i<xml.childNodes.length;i++){
varitem=xml.childNodes.item(i);
varnodeName=item.nodeName;
if(typeof(obj[nodeName])=="undefined"){
obj[nodeName]=xmlToJson(item);
}else{
if(typeof(obj[nodeName].length)=="undefined"){
varold=obj[nodeName];
obj[nodeName]=[];
obj[nodeName].push(old);
}
obj[nodeName].push(xmlToJson(item));
}
}
}
returnobj;
};
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