javahttp源码

⑴ 求一段java模拟Http请求的代码(带注释)

用httpclient就行
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.ResponseHandler;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet("http://www.google.com");
httpGet.addHeader("MyHeader", "MyValue");

try {
String body = httpClient.execute(httpGet, new ResponseHandler<String>() {

@Override
public String handleResponse(HttpResponse response) throws IOException {
Header firstHeader = response.getFirstHeader("MyHeader");
String headerValue = firstHeader.getValue();
return EntityUtils.toString(response.getEntity());
}
});
} catch (IOException e) {
e.printStackTrace();
}

⑵ 源码看的很头疼，java中的HttpURLConnection类中的，有高人吗

建议使用httpclient框架，这个比HttpURLConnection好用多了，以下是请求示例：
1. GET 方式传递参数

//先将参数放入List，再对参数进行URL编码
List<BasicNameValuePair> params = new LinkedList<BasicNameValuePair>();
params.add(new BasicNameValuePair("param1", "数据")); //增加参数1
params.add(new BasicNameValuePair("param2", "value2"));//增加参数2
String param = URLEncodedUtils.format(params, "UTF-8");//对参数编码
String baseUrl = "服务器接口完整URL";
HttpGet getMethod = new HttpGet(baseUrl + "?" + param);//将URL与参数拼接
HttpClient httpClient = new DefaultHttpClient();
try {
HttpResponse response = httpClient.execute(getMethod); //发起GET请求
Log.i(TAG, "resCode = " + response.getStatusLine().getStatusCode()); //获取响应码
Log.i(TAG, "result = " + EntityUtils.toString(response.getEntity(), "utf-8"));//获取服务器响应内容
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}

2. POST方式 方式传递参数
//和GET方式一样，先将参数放入List
params = new LinkedList<BasicNameValuePair>();
params.add(new BasicNameValuePair("param1", "Post方法"));//增加参数1
params.add(new BasicNameValuePair("param2", "第二个参数"));//增加参数2
try {
HttpPost postMethod = new HttpPost(baseUrl);//创建一个post请求
postMethod.setEntity(new UrlEncodedFormEntity(params, "utf-8")); //将参数填入POST Entity中
HttpResponse response = httpClient.execute(postMethod); //执行POST方法
Log.i(TAG, "resCode = " + response.getStatusLine().getStatusCode()); //获取响应码
Log.i(TAG, "result = " + EntityUtils.toString(response.getEntity(), "utf-8")); //获取响应内容
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}

⑶ java写的发送http头的程序

看得我很是纠结
你这是socket连接还是http连接呀？
建议使用httpClient

⑷ java http请求时怎么返回错误页面源码 （例如返回404时的页面源码），我的程序遇到这种就报错。

用getErrorStream();

Scanner s;
if (connection.getResponseCode() != 200) {
s = new Scanner(connection.getErrorStream());
} else {
s = new Scanner(connection.getInputStream());
}

⑸ 怎么在电脑上运行Java源程序代码

http://hi..com/%D1%EE%5F%C1%F5/blog/item/55d15c35a8b7ca87a71e122e.html
上面的网址是java扫雷的源代码

要运行，首先要配置环境变量（方法可参考网上）
其次找到程序所在的盘符目录，比如java扫雷程序，放在了
E:\Java扫雷中，那么在DOS下就要到此目录

然后依次输入javac *.java（编译）
java *（运行）即可