androidjson请求

Ⅰ Android请求php服务器的JSON问题

因为PHP会默认添加一个bom头信息 有几个字节 你得去掉 一般是四个字节
package cn.image.sky.util;

import java.io.*;

/**
* Generic unicode textreader, which will use BOM mark to identify the encoding
* to be used. If BOM is not found then use a given default or system encoding.
*/
public class UnicodeReader extends Reader {
PushbackInputStream internalIn;
InputStreamReader internalIn2 = null;
String defaultEnc;

private static final int BOM_SIZE = 4;

/**
*
* @param in
* inputstream to be read
* @param defaultEnc
* default encoding if stream does not have BOM marker. Give NULL
* to use system-level default.
*/
UnicodeReader(InputStream in, String defaultEnc) {
internalIn = new PushbackInputStream(in, BOM_SIZE);
this.defaultEnc = defaultEnc;
}

public String getDefaultEncoding() {
return defaultEnc;
}

/**
* Get stream encoding or NULL if stream is uninitialized. Call init() or
* read() method to initialize it.
*/
public String getEncoding() {
if (internalIn2 == null)
return null;
return internalIn2.getEncoding();
}

/**
* Read-ahead four bytes and check for BOM marks. Extra bytes are unread
* back to the stream, only BOM bytes are skipped.
*/
protected void init() throws IOException {
if (internalIn2 != null)
return;

String encoding;
byte bom[] = new byte[BOM_SIZE];
int n, unread;
n = internalIn.read(bom, 0, bom.length);

if ((bom[0] == (byte) 0x00) && (bom[1] == (byte) 0x00)
&& (bom[2] == (byte) 0xFE) && (bom[3] == (byte) 0xFF)) {
encoding = "UTF-32BE";
unread = n - 4;
} else if ((bom[0] == (byte) 0xFF) && (bom[1] == (byte) 0xFE)
&& (bom[2] == (byte) 0x00) && (bom[3] == (byte) 0x00)) {
encoding = "UTF-32LE";
unread = n - 4;
} else if ((bom[0] == (byte) 0xEF) && (bom[1] == (byte) 0xBB)
&& (bom[2] == (byte) 0xBF)) {
encoding = "UTF-8";
unread = n - 3;
} else if ((bom[0] == (byte) 0xFE) && (bom[1] == (byte) 0xFF)) {
encoding = "UTF-16BE";
unread = n - 2;
} else if ((bom[0] == (byte) 0xFF) && (bom[1] == (byte) 0xFE)) {
encoding = "UTF-16LE";
unread = n - 2;
} else {
// Unicode BOM mark not found, unread all bytes
encoding = defaultEnc;
unread = n;
}
// System.out.println("read=" + n + ", unread=" + unread);

if (unread > 0)
internalIn.unread(bom, (n - unread), unread);

// Use given encoding
if (encoding == null) {
internalIn2 = new InputStreamReader(internalIn);
} else {
internalIn2 = new InputStreamReader(internalIn, encoding);
}
}

public void close() throws IOException {
init();
internalIn2.close();
}

public int read(char[] cbuf, int off, int len) throws IOException {
init();
return internalIn2.read(cbuf, off, len);
}

}

这个类 你看看 可以解决你的问题

Ⅱ Android 解析json问题

///http地址
		StringhttpUrl=ip+":"+端口号+"/loginbyandroid/validate.do";
		//HttpPost连接对象
		HttpPosthttpRequest=newHttpPost(httpUrl);
		//使用NameValuePair来保存要传递的Post参数
		List<NameValuePair>params=newArrayList<NameValuePair>();
		//添加要传递的参数
		params.add(newBasicNameValuePair("loginId","value"));
		params.add(newBasicNameValuePair("password","value"));
		//设置字符集
		HttpEntityhttpentity;
		try{
			httpentity=newUrlEncodedFormEntity(params,"utf-8");

			//请求httpRequest
			httpRequest.setEntity(httpentity);
			//取得默认的HttpClient
			HttpClienthttpclient=newDefaultHttpClient();
			//取得HttpResponse
			HttpResponsehttpResponse;
			httpResponse=httpclient.execute(httpRequest);
			//HttpStatus.SC_OK表示连接成功
			if(httpResponse.getStatusLine().getStatusCode()==HttpStatus.SC_OK){
				//取得返回的字符串
				StringstrResult=EntityUtils.toString(httpResponse
						.getEntity());
				JSONArrayjsonArray=newJSONArray(strResult);
				for(inti=0;i<jsonArray.length();i++){
					JSONObjectjsonObject=(JSONObject)jsonArray.opt(i);
					Stringsuccess=jsonObject.getString("success");
					StringJSESSIONID=jsonObject.getString("JSESSIONID");
					StringloginName=jsonObject.getString("loginName");
					Stringorgname=jsonObject.getString("orgname");
					System.out.println("success="+success
							+"JSESSIONID="+JSESSIONID+"loginName="
							+loginName+"orgname="+orgname);
				}
			}else{
				System.out.println("请求错误!");
			}
		}catch(ClientProtocolExceptione){
			e.printStackTrace();
		}catch(IOExceptione){
			e.printStackTrace();
		}

Ⅲ android 中如何在 手机端发送json请求，服务器得到json类型的响应结果

android中要求向服务器发送get,然猴得到响应数据

Ⅳ android post请求json参数list认证怎样实现

如果采用post请求，与后台传送参数采用json格式，那么可以采用如下的形式包装参数：
JSONObject params = new JSONObject();
params.put("signature",signature);
params.put("timestamp",timestamp);
params.put("nouce",nouce);
params.put("parnter",parnter);
params.put("access_token",access_token);
包装之后可以采用一个访问网络的工具类HttpClient访问后台接口就可以了
我不知道你说的是不是这个意思，希望帮到你

Ⅳ java怎么接收android请求过来的json数据

java接收android请求json数据的方法：

• 如果发送的没有参数名称你可以直接得到请求体，如
  InputStreaminputStream=urlConnection.getInputStream();
  Stringencoding=urlConnection.getContentEncoding();
  Stringbody=IOUtils.toString(inputStream,encoding);
  System.out.println(body);

• 如果body就是那个json内容使用fastjson进行解析就可以了
  JSONObjectmap=JSON.parseObject(body);
  System.out.println(map.getString("mobileNo"));//还是System.out.println(map.get("mobileNo"));?具体看一下接口文档

• 或者
  Mapmap=JSON.parseObject(body,Map.class);
  System.out.println(map.get("mobileNo"));
  

Ⅵ android怎么使用okhttputils发送json请求数据

服务端是用servlet写的吧 直接调用response的out输出即可 response.getWriter().print("20"); 这样安卓得到的返回值就是20