vbmd5加密解密
1. 求VB.NET的MD5算法调用
下面是完整的类，可以设置任意密码
'DES及md5加密解密----添加引用中添加对system.web的引用。
ImportsSystem.Security.Cryptography
ImportsSystem
ImportsSystem.Text
ImportsSystem.Web
'''<summary>
'''DES加密类
'''</summary>
'''<remarks></remarks>
PublicClassDESEncrypt
PublicSubDESEncrypt()
EndSub
PublicSharedFunctionEncrypt(ByValTextAsString)AsString
ReturnEncrypt(Text,"12345678")
EndFunction
PublicSharedFunctionEncrypt(ByValTextAsString,ByValsKeyAsString)AsString
()
DiminputByteArrayAsByte()
inputByteArray=Encoding.Default.GetBytes(Text)
des.Key=ASCIIEncoding.ASCII.GetBytes(System.Web.Security.FormsAuthentication.(sKey,"md5").Substring(0,8))
des.IV=ASCIIEncoding.ASCII.GetBytes(System.Web.Security.FormsAuthentication.(sKey,"md5").Substring(0,8))
DimmsAsNewSystem.IO.MemoryStream()
DimcsAsNewCryptoStream(ms,des.CreateEncryptor(),CryptoStreamMode.Write)
cs.Write(inputByteArray,0,inputByteArray.Length)
cs.FlushFinalBlock()
DimretAsNewStringBuilder()
DimbAsByte
ForEachbInms.ToArray()
ret.AppendFormat("{0:X2}",b)
Next
Returnret.ToString()
EndFunction
PublicSharedFunctionDecrypt(ByValTextAsString)AsString
ReturnDecrypt(Text,"12345678")
EndFunction
PublicSharedFunctionDecrypt(ByValTextAsString,ByValsKeyAsString)AsString
()
DimlenAsInteger
len=Text.Length/2
DiminputByteArray(len-1)AsByte
Dimx,iAsInteger
Forx=0Tolen-1
i=Convert.ToInt32(Text.Substring(x*2,2),16)
inputByteArray(x)=CType(i,Byte)
Next
des.Key=ASCIIEncoding.ASCII.GetBytes(System.Web.Security.FormsAuthentication.(sKey,"md5").Substring(0,8))
des.IV=ASCIIEncoding.ASCII.GetBytes(System.Web.Security.FormsAuthentication.(sKey,"md5").Substring(0,8))
DimmsAsNewSystem.IO.MemoryStream()
DimcsAsNewCryptoStream(ms,des.CreateDecryptor(),CryptoStreamMode.Write)
cs.Write(inputByteArray,0,inputByteArray.Length)
cs.FlushFinalBlock()
ReturnEncoding.Default.GetString(ms.ToArray())
EndFunction
EndClass
'以下是调用方法
PublicClassForm1
PrivateSubButton1_Click(ByValsenderAsSystem.Object,ByValeAsSystem.EventArgs)HandlesButton1.Click'加密
Dimstr_EncryptAsString=DESEncrypt.Encrypt("你要加密的文本，可以是任意长度","密码，可以很长，如果省略这个参数就是默认的12345678")
EndSub
PrivateSubButton2_Click(ByValsenderAsSystem.Object,ByValeAsSystem.EventArgs)HandlesButton2.Click'解密
Dimstr_DecryptAsString=DESEncrypt.Decrypt("你要解密的文本,可以是任意长度","加密时用到的密码，如果省略这个参数就是默认的12345678")
EndSub
2. MD5真的没有可逆性么 求VB 中 MD5加密解密.
MD5
不支持反向解密的，别费这个心思了吧。
建议用替代法，直接把知道的Md5码，覆盖这个。
3. 用VB.net编写一个加密解密软件
"采用DES算法"这个说法不明确，首先是使用多少位的DES进行加密，通常是128位或192位，其次是，要先把主密钥转化成散列，才能供DES进行加密，转化的方法是什么没有明确，通常是md5，所以有的银行卡说是128位md5 3DS就是指用md5转换主密钥散列，用DES进行加密，但是DES本身是64位（包含校验码），2DES是128位，3DES是192位，但是没有2DES的叫法，所以128位、192位统称3DES
要完整的md5+3DS实例，需要100分以上，要不到我的空间中查找相关的文章
4. 求vb md5加解密
代码很多。仔细看先建一个类Class Mole 取名为ClsAPIMD5复制下面的代码到类里：'API 做的MD5类Option Explicit
Private Declare Function CryptAcquireContext Lib "advapi32.dll" _
Alias "CryptAcquireContextA" ( _
ByRef phProv As Long, _
ByVal pszContainer As String, _
ByVal pszProvider As String, _
ByVal dwProvType As Long, _
ByVal dwFlags As Long) As LongPrivate Declare Function CryptReleaseContext Lib "advapi32.dll" ( _
ByVal hProv As Long, _
ByVal dwFlags As Long) As LongPrivate Declare Function CryptCreateHash Lib "advapi32.dll" ( _
ByVal hProv As Long, _
ByVal Algid As Long, _
ByVal hKey As Long, _
ByVal dwFlags As Long, _
ByRef phHash As Long) As LongPrivate Declare Function CryptDestroyHash Lib "advapi32.dll" ( _
ByVal hHash As Long) As LongPrivate Declare Function CryptHashData Lib "advapi32.dll" ( _
ByVal hHash As Long, _
pbData As Any, _
ByVal dwDataLen As Long, _
ByVal dwFlags As Long) As LongPrivate Declare Function CryptGetHashParam Lib "advapi32.dll" ( _
ByVal hHash As Long, _
ByVal dwParam As Long, _
pbData As Any, _
pdwDataLen As Long, _
ByVal dwFlags As Long) As LongPrivate Const PROV_RSA_FULL = 1Private Const ALG_CLASS_HASH = 32768Private Const ALG_TYPE_ANY = 0Private Const ALG_SID_MD2 = 1
Private Const ALG_SID_MD4 = 2
Private Const ALG_SID_MD5 = 3
Private Const ALG_SID_SHA1 = 4Enum HashAlgorithm
md2 = ALG_CLASS_HASH Or ALG_TYPE_ANY Or ALG_SID_MD2
MD4 = ALG_CLASS_HASH Or ALG_TYPE_ANY Or ALG_SID_MD4
md5 = ALG_CLASS_HASH Or ALG_TYPE_ANY Or ALG_SID_MD5
SHA1 = ALG_CLASS_HASH Or ALG_TYPE_ANY Or ALG_SID_SHA1
End EnumPrivate Const HP_HASHVAL = 2
Private Const HP_HASHSIZE = 4Function HashString( _
ByVal Str As String, _
Optional ByVal Algorithm As HashAlgorithm = md5) As String
Dim hCtx As Long
Dim hHash As Long
Dim lRes As Long
Dim lLen As Long
Dim lIdx As Long
Dim abData() As Byte ' Get default provider context handle
lRes = CryptAcquireContext(hCtx, vbNullString, _
vbNullString, PROV_RSA_FULL, 0) If lRes <> 0 Then ' Create the hash
lRes = CryptCreateHash(hCtx, Algorithm, 0, 0, hHash) If lRes <> 0 Then ' Hash the string
lRes = CryptHashData(hHash, ByVal Str, Len(Str), 0) If lRes <> 0 Then
' Get the hash lenght
lRes = CryptGetHashParam(hHash, HP_HASHSIZE, lLen, 4, 0) If lRes <> 0 Then ' Initialize the buffer
ReDim abData(0 To lLen - 1) ' Get the hash value
lRes = CryptGetHashParam(hHash, HP_HASHVAL, abData(0), lLen, 0) If lRes <> 0 Then ' Convert value to hex string
For lIdx = 0 To UBound(abData)
HashString = HashString & _
Right$("0" & Hex$(abData(lIdx)), 2)
Next End If End If End If ' Release the hash handle
CryptDestroyHash hHash End If
End If ' Release the provider context
CryptReleaseContext hCtx, 0 ' Raise an error if lRes = 0
If lRes = 0 Then Err.Raise Err.LastDllErrorEnd FunctionFunction HashFile( _
ByVal Filename As String, _
Optional ByVal Algorithm As HashAlgorithm = md5) As String
Dim hCtx As Long
Dim hHash As Long
Dim lFile As Long
Dim lRes As Long
Dim lLen As Long
Dim lIdx As Long
Dim abHash() As Byte ' Check if the file exists (not the best method BTW!)
If Len(Dir$(Filename)) = 0 Then Err.Raise 53
' Get default provider context handle
lRes = CryptAcquireContext(hCtx, vbNullString, _
vbNullString, PROV_RSA_FULL, 0) If lRes = 0 And Err.LastDllError = &H80090016 Then
' There's no default keyset container!!!
' Get the provider context and create
' a default keyset container
lRes = CryptAcquireContext(hCtx, vbNullString, _
vbNullString, PROV_RSA_FULL, CRYPT_NEWKEYSET)
End If
If lRes <> 0 Then ' Create the hash
lRes = CryptCreateHash(hCtx, Algorithm, 0, 0, hHash) If lRes <> 0 Then ' Get a file handle
lFile = FreeFile
' Open the file
Open Filename For Binary As lFile
If Err.Number = 0 Then
Const BLOCK_SIZE As Long = 32 * 1024& ' 32K
ReDim abBlock(1 To BLOCK_SIZE) As Byte
Dim lCount As Long
Dim lBlocks As Long
Dim lLastBlock As Long
' Calculate how many full blocks
' the file contains
lBlocks = LOF(lFile) \ BLOCK_SIZE
' Calculate the remaining data length
lLastBlock = LOF(lFile) - lBlocks * BLOCK_SIZE
' Hash the blocks
For lCount = 1 To lBlocks
Get lFile, , abBlock
' Add the chunk to the hash
lRes = CryptHashData(hHash, abBlock(1), BLOCK_SIZE, 0)
' Stop the loop if CryptHashData fails
If lRes = 0 Then Exit For
Next ' Is there more data?
If lLastBlock > 0 And lRes <> 0 Then
' Get the last block
ReDim abBlock(1 To lLastBlock) As Byte
Get lFile, , abBlock
' Hash the last block
lRes = CryptHashData(hHash, abBlock(1), lLastBlock, 0)
End If
' Close the file
Close lFile
End If If lRes <> 0 Then
' Get the hash lenght
lRes = CryptGetHashParam(hHash, HP_HASHSIZE, lLen, 4, 0) If lRes <> 0 Then ' Initialize the buffer
ReDim abHash(0 To lLen - 1) ' Get the hash value
lRes = CryptGetHashParam(hHash, HP_HASHVAL, abHash(0), lLen, 0) If lRes <> 0 Then ' Convert value to hex string
For lIdx = 0 To UBound(abHash)
HashFile = HashFile & _
Right$("0" & Hex$(abHash(lIdx)), 2)
Next End If End If End If ' Release the hash handle
CryptDestroyHash hHash End If
End If ' Release the provider context
CryptReleaseContext hCtx, 0 ' Raise an error if lRes = 0
If lRes = 0 Then Err.Raise Err.LastDllErrorEnd Function
使用时：Private Sub Form_Load()
Dim mymd5 As New ClsAPIMD5
Dim md5str As String
md5str = mymd5.HashString(" test", md5)
Set mymd5 = Nothing '用完释放内存End Sub
5. 用VB实现MD5加密
md5加密运算是不可逆的，就是说不能通过那一串古古怪怪的东西算出它原始的样子。
以下提供VB可用的16位和32位MD5加密函数代码：
PrivateConstBITS_TO_A_BYTE=8
PrivateConstBYTES_TO_A_WORD=4
PrivateConstBITS_TO_A_WORD=32
Privatem_lOnBits(30)
Privatem_l2Power(30)
PrivateFunctionLShift(lValue,iShiftBits)
IfiShiftBits=0Then
LShift=lValue
ExitFunction
ElseIfiShiftBits=31Then
IflValueAnd1Then
LShift=&H80000000
Else
LShift=0
EndIf
ExitFunction
ElseIfiShiftBits<0OriShiftBits>31Then
Err.Raise6
EndIf
If(lValueAndm_l2Power(31-iShiftBits))Then
LShift=((lValueAndm_lOnBits(31-(iShiftBits+1)))*m_l2Power(iShiftBits))Or&H80000000
Else
LShift=((lValueAndm_lOnBits(31-iShiftBits))*m_l2Power(iShiftBits))
EndIf
EndFunction
PrivateFunctionRShift(lValue,iShiftBits)
IfiShiftBits=0Then
RShift=lValue
ExitFunction
ElseIfiShiftBits=31Then
IflValueAnd&H80000000Then
RShift=1
Else
RShift=0
EndIf
ExitFunction
ElseIfiShiftBits<0OriShiftBits>31Then
Err.Raise6
EndIf
RShift=(lValueAnd&H7FFFFFFE)m_l2Power(iShiftBits)
If(lValueAnd&H80000000)Then
RShift=(RShiftOr(&H40000000m_l2Power(iShiftBits-1)))
EndIf
EndFunction
PrivateFunctionRotateLeft(lValue,iShiftBits)
RotateLeft=LShift(lValue,iShiftBits)OrRShift(lValue,(32-iShiftBits))
EndFunction
PrivateFunctionAddUnsigned(lX,lY)
DimlX4
DimlY4
DimlX8
DimlY8
DimlResult
lX8=lXAnd&H80000000
lY8=lYAnd&H80000000
lX4=lXAnd&H40000000
lY4=lYAnd&H40000000
lResult=(lXAnd&H3FFFFFFF)+(lYAnd&H3FFFFFFF)
IflX4AndlY4Then
lResult=lResultXor&H80000000XorlX8XorlY8
ElseIflX4OrlY4Then
IflResultAnd&H40000000Then
lResult=lResultXor&HC0000000XorlX8XorlY8
Else
lResult=lResultXor&H40000000XorlX8XorlY8
EndIf
Else
lResult=lResultXorlX8XorlY8
EndIf
AddUnsigned=lResult
EndFunction
PrivateFunctionmd5_F(x,y,z)
md5_F=(xAndy)Or((Notx)Andz)
EndFunction
PrivateFunctionmd5_G(x,y,z)
md5_G=(xAndz)Or(yAnd(Notz))
EndFunction
PrivateFunctionmd5_H(x,y,z)
md5_H=(xXoryXorz)
EndFunction
PrivateFunctionmd5_I(x,y,z)
md5_I=(yXor(xOr(Notz)))
EndFunction
PrivateSubmd5_FF(a,b,c,d,x,s,ac)
a=AddUnsigned(a,AddUnsigned(AddUnsigned(md5_F(b,c,d),x),ac))
a=RotateLeft(a,s)
a=AddUnsigned(a,b)
EndSub
PrivateSubmd5_GG(a,b,c,d,x,s,ac)
a=AddUnsigned(a,AddUnsigned(AddUnsigned(md5_G(b,c,d),x),ac))
a=RotateLeft(a,s)
a=AddUnsigned(a,b)
EndSub
PrivateSubmd5_HH(a,b,c,d,x,s,ac)
a=AddUnsigned(a,AddUnsigned(AddUnsigned(md5_H(b,c,d),x),ac))
a=RotateLeft(a,s)
a=AddUnsigned(a,b)
EndSub
PrivateSubmd5_II(a,b,c,d,x,s,ac)
a=AddUnsigned(a,AddUnsigned(AddUnsigned(md5_I(b,c,d),x),ac))
a=RotateLeft(a,s)
a=AddUnsigned(a,b)
EndSub
(sMessage)
DimlMessageLength
DimlNumberOfWords
DimlWordArray()
DimlBytePosition
DimlByteCount
DimlWordCount
ConstMODULUS_BITS=512
ConstCONGRUENT_BITS=448
lMessageLength=Len(sMessage)
lNumberOfWords=(((lMessageLength+((MODULUS_BITS-CONGRUENT_BITS)BITS_TO_A_BYTE))(MODULUS_BITSBITS_TO_A_BYTE))+1)*(MODULUS_BITSBITS_TO_A_WORD)
ReDimlWordArray(lNumberOfWords-1)
lBytePosition=0
lByteCount=0
DoUntillByteCount>=lMessageLength
lWordCount=lByteCountBYTES_TO_A_WORD
lBytePosition=(lByteCountModBYTES_TO_A_WORD)*BITS_TO_A_BYTE
lWordArray(lWordCount)=lWordArray(lWordCount)OrLShift(Asc(Mid(sMessage,lByteCount+1,1)),lBytePosition)
lByteCount=lByteCount+1
Loop
lWordCount=lByteCountBYTES_TO_A_WORD
lBytePosition=(lByteCountModBYTES_TO_A_WORD)*BITS_TO_A_BYTE
lWordArray(lWordCount)=lWordArray(lWordCount)OrLShift(&H80,lBytePosition)
lWordArray(lNumberOfWords-2)=LShift(lMessageLength,3)
lWordArray(lNumberOfWords-1)=RShift(lMessageLength,29)
ConvertToWordArray=lWordArray
EndFunction
PrivateFunctionWordToHex(lValue)
DimlByte
DimlCount
ForlCount=0To3
lByte=RShift(lValue,lCount*BITS_TO_A_BYTE)Andm_lOnBits(BITS_TO_A_BYTE-1)
WordToHex=WordToHex&Right("0"&Hex(lByte),2)
Next
EndFunction
PublicFunctionMD5(sMessage,stype)
m_lOnBits(0)=CLng(1)
m_lOnBits(1)=CLng(3)
m_lOnBits(2)=CLng(7)
m_lOnBits(3)=CLng(15)
m_lOnBits(4)=CLng(31)
m_lOnBits(5)=CLng(63)
m_lOnBits(6)=CLng(127)
m_lOnBits(7)=CLng(255)
m_lOnBits(8)=CLng(511)
m_lOnBits(9)=CLng(1023)
m_lOnBits(10)=CLng(2047)
m_lOnBits(11)=CLng(4095)
m_lOnBits(12)=CLng(8191)
m_lOnBits(13)=CLng(16383)
m_lOnBits(14)=CLng(32767)
m_lOnBits(15)=CLng(65535)
m_lOnBits(16)=CLng(131071)
m_lOnBits(17)=CLng(262143)
m_lOnBits(18)=CLng(524287)
m_lOnBits(19)=CLng(1048575)
m_lOnBits(20)=CLng(2097151)
m_lOnBits(21)=CLng(4194303)
m_lOnBits(22)=CLng(8388607)
m_lOnBits(23)=CLng(16777215)
m_lOnBits(24)=CLng(33554431)
m_lOnBits(25)=CLng(67108863)
m_lOnBits(26)=CLng(134217727)
m_lOnBits(27)=CLng(268435455)
m_lOnBits(28)=CLng(536870911)
m_lOnBits(29)=CLng(1073741823)
m_lOnBits(30)=CLng(2147483647)
m_l2Power(0)=CLng(1)
m_l2Power(1)=CLng(2)
m_l2Power(2)=CLng(4)
m_l2Power(3)=CLng(8)
m_l2Power(4)=CLng(16)
m_l2Power(5)=CLng(32)
m_l2Power(6)=CLng(64)
m_l2Power(7)=CLng(128)
m_l2Power(8)=CLng(256)
m_l2Power(9)=CLng(512)
m_l2Power(10)=CLng(1024)
m_l2Power(11)=CLng(2048)
m_l2Power(12)=CLng(4096)
m_l2Power(13)=CLng(8192)
m_l2Power(14)=CLng(16384)
m_l2Power(15)=CLng(32768)
m_l2Power(16)=CLng(65536)
m_l2Power(17)=CLng(131072)
m_l2Power(18)=CLng(262144)
m_l2Power(19)=CLng(524288)
m_l2Power(20)=CLng(1048576)
m_l2Power(21)=CLng(2097152)
m_l2Power(22)=CLng(4194304)
m_l2Power(23)=CLng(8388608)
m_l2Power(24)=CLng(16777216)
m_l2Power(25)=CLng(33554432)
m_l2Power(26)=CLng(67108864)
m_l2Power(27)=CLng(134217728)
m_l2Power(28)=CLng(268435456)
m_l2Power(29)=CLng(536870912)
m_l2Power(30)=CLng(1073741824)
Dimx
Dimk
DimAA
DimBB
DimCC
DimDD
Dima
Dimb
Dimc
Dimd
ConstS11=7
ConstS12=12
ConstS13=17
ConstS14=22
ConstS21=5
ConstS22=9
ConstS23=14
ConstS24=20
ConstS31=4
ConstS32=11
ConstS33=16
ConstS34=23
ConstS41=6
ConstS42=10
ConstS43=15
ConstS44=21
x=ConvertToWordArray(sMessage)
a=&H67452301
b=&HEFCDAB89
c=&H98BADCFE
d=&H10325476
Fork=0ToUBound(x)Step16
AA=a
BB=b
CC=c
DD=d
md5_FFa,b,c,d,x(k+0),S11,&HD76AA478
md5_FFd,a,b,c,x(k+1),S12,&HE8C7B756
md5_FFc,d,a,b,x(k+2),S13,&H242070DB
md5_FFb,c,d,a,x(k+3),S14,&HC1BDCEEE
md5_FFa,b,c,d,x(k+4),S11,&HF57C0FAF
md5_FFd,a,b,c,x(k+5),S12,&H4787C62A
md5_FFc,d,a,b,x(k+6),S13,&HA8304613
md5_FFb,c,d,a,x(k+7),S14,&HFD469501
md5_FFa,b,c,d,x(k+8),S11,&H698098D8
md5_FFd,a,b,c,x(k+9),S12,&H8B44F7AF
md5_FFc,d,a,b,x(k+10),S13,&HFFFF5BB1
md5_FFb,c,d,a,x(k+11),S14,&H895CD7BE
md5_FFa,b,c,d,x(k+12),S11,&H6B901122
md5_FFd,a,b,c,x(k+13),S12,&HFD987193
md5_FFc,d,a,b,x(k+14),S13,&HA679438E
md5_FFb,c,d,a,x(k+15),S14,&H49B40821
md5_GGa,b,c,d,x(k+1),S21,&HF61E2562
md5_GGd,a,b,c,x(k+6),S22,&HC040B340
md5_GGc,d,a,b,x(k+11),S23,&H265E5A51
md5_GGb,c,d,a,x(k+0),S24,&HE9B6C7AA
md5_GGa,b,c,d,x(k+5),S21,&HD62F105D
md5_GGd,a,b,c,x(k+10),S22,&H2441453
md5_GGc,d,a,b,x(k+15),S23,&HD8A1E681
md5_GGb,c,d,a,x(k+4),S24,&HE7D3FBC8
md5_GGa,b,c,d,x(k+9),S21,&H21E1CDE6
md5_GGd,a,b,c,x(k+14),S22,&HC33707D6
md5_GGc,d,a,b,x(k+3),S23,&HF4D50D87
md5_GGb,c,d,a,x(k+8),S24,&H455A14ED
md5_GGa,b,c,d,x(k+13),S21,&HA9E3E905
md5_GGd,a,b,c,x(k+2),S22,&HFCEFA3F8
md5_GGc,d,a,b,x(k+7),S23,&H676F02D9
md5_GGb,c,d,a,x(k+12),S24,&H8D2A4C8A
md5_HHa,b,c,d,x(k+5),S31,&HFFFA3942
md5_HHd,a,b,c,x(k+8),S32,&H8771F681
md5_HHc,d,a,b,x(k+11),S33,&H6D9D6122
md5_HHb,c,d,a,x(k+14),S34,&HFDE5380C
md5_HHa,b,c,d,x(k+1),S31,&HA4BEEA44
md5_HHd,a,b,c,x(k+4),S32,&H4BDECFA9
md5_HHc,d,a,b,x(k+7),S33,&HF6BB4B60
md5_HHb,c,d,a,x(k+10),S34,&HBEBFBC70
md5_HHa,b,c,d,x(k+13),S31,&H289B7EC6
md5_HHd,a,b,c,x(k+0),S32,&HEAA127FA
md5_HHc,d,a,b,x(k+3),S33,&HD4EF3085
md5_HHb,c,d,a,x(k+6),S34,&H4881D05
md5_HHa,b,c,d,x(k+9),S31,&HD9D4D039
md5_HHd,a,b,c,x(k+12),S32,&HE6DB99E5
md5_HHc,d,a,b,x(k+15),S33,&H1FA27CF8
md5_HHb,c,d,a,x(k+2),S34,&HC4AC5665
md5_IIa,b,c,d,x(k+0),S41,&HF4292244
md5_IId,a,b,c,x(k+7),S42,&H432AFF97
md5_IIc,d,a,b,x(k+14),S43,&HAB9423A7
md5_IIb,c,d,a,x(k+5),S44,&HFC93A039
md5_IIa,b,c,d,x(k+12),S41,&H655B59C3
md5_IId,a,b,c,x(k+3),S42,&H8F0CCC92
md5_IIc,d,a,b,x(k+10),S43,&HFFEFF47D
md5_IIb,c,d,a,x(k+1),S44,&H85845DD1
md5_IIa,b,c,d,x(k+8),S41,&H6FA87E4F
md5_IId,a,b,c,x(k+15),S42,&HFE2CE6E0
md5_IIc,d,a,b,x(k+6),S43,&HA3014314
md5_IIb,c,d,a,x(k+13),S44,&H4E0811A1
md5_IIa,b,c,d,x(k+4),S41,&HF7537E82
md5_IId,a,b,c,x(k+11),S42,&HBD3AF235
md5_IIc,d,a,b,x(k+2),S43,&H2AD7D2BB
md5_IIb,c,d,a,x(k+9),S44,&HEB86D391
a=AddUnsigned(a,AA)
b=AddUnsigned(b,BB)
c=AddUnsigned(c,CC)
d=AddUnsigned(d,DD)
Next
Ifstype=32Then
MD5=LCase(WordToHex(a)&WordToHex(b)&WordToHex(c)&WordToHex(d))
Else
MD5=LCase(WordToHex(b)&WordToHex(c))
EndIf
EndFunction
'下面是测试代码
Subtest()
MsgBoxMD5("a",16)'16位加密
MsgBoxMD5("a",32)'32位加密
EndSub
6. MD5加密算法的解密源代码(VB的)
MD5加密算法: 见附件..
解密没有的,MD5不支持解密,因为在加密的时候是随机移位数的..
7. VB MD5加密解密的代码
Dim md5 As New MD5CryptoServiceProvider
Dim username As Byte() = (New ASCIIEncoding).GetBytes(TextBox1.Text)
'转换为哈希值Byte数组
Dim mdByte As Byte() = md5.ComputeHash(username)
'Dim mdString As String = System.BitConverter.ToString(mdByte)
Dim mdString As String = (New ASCIIEncoding).GetString(mdByte)
TextBox2.Text = mdString
md5理论上是不可破解的，要对照，只能再次加密后对照，网上也有些专门破解的网站，不过我想你要的不是那个吧
8. VB加密解密，急！！
<%
'----加密/解密 函数------
%>
<%
dim sBASE_64_CHARACTERS,varchar,varasc
dim len1
dim i
dim m3
sBASE_64_CHARACTERS = "+/"
sBASE_64_CHARACTERS = strUnicode2Ansi(sBASE_64_CHARACTERS)
Function strUnicodeLen(asContents)
'计算unicode字符串的Ansi编码的长度
asContents1="a"&asContents
len1=len(asContents1)
k=0
for i=1 to len1
asc1=asc(mid(asContents1,i,1))
if asc1<0 then asc1=65536+asc1
if asc1>255 then
k=k+2
else
k=k+1
end if
next
strUnicodeLen=k-1
End Function
Function strUnicode2Ansi(asContents)
'将Unicode编码的字符串，转换成Ansi编码的字符串
strUnicode2Ansi=""
len1=len(asContents)
for i=1 to len1
varchar=mid(asContents,i,1)
varasc=asc(varchar)
if varasc<0 then varasc=varasc+65536
if varasc>255 then
varHex=Hex(varasc)
varlow=left(varHex,2)
varhigh=right(varHex,2)
strUnicode2Ansi=strUnicode2Ansi & chrb("&H" & varlow ) & chrb("&H" & varhigh )
else
strUnicode2Ansi=strUnicode2Ansi & chrb(varasc)
end if
next
End function
Function strAnsi2Unicode(asContents)
'将Ansi编码的字符串，转换成Unicode编码的字符串
strAnsi2Unicode = ""
len1=lenb(asContents)
if len1=0 then exit function
for i=1 to len1
varchar=midb(asContents,i,1)
varasc=ascb(varchar)
if varasc > 127 then
strAnsi2Unicode = strAnsi2Unicode & chr(ascw(midb(asContents,i+1,1) & varchar))
i=i+1
else
strAnsi2Unicode = strAnsi2Unicode & chr(varasc)
end if
next
End function
Function Base64encode(asContents)
'将Ansi编码的字符串进行Base64编码
'asContents应当是ANSI编码的字符串（二进制的字符串也可以）
Dim lnPosition
Dim lsResult
Dim Char1
Dim Char2
Dim Char3
Dim Char4
Dim Byte1
Dim Byte2
Dim Byte3
Dim SaveBits1
Dim SaveBits2
Dim lsGroupBinary
Dim lsGroup64
Dim m4,len1,len2
len1=Lenb(asContents)
if len1<1 then
Base64encode=""
exit Function
end if
m3=Len1 Mod 3
If M3 > 0 Then asContents = asContents & String(3-M3, chrb(0))
IF m3 > 0 THEN
len1=len1+(3-m3)
len2=len1-3
else
len2=len1
end if
lsResult = ""
For lnPosition = 1 To len2 Step 3
lsGroup64 = ""
lsGroupBinary = Midb(asContents, lnPosition, 3)
Byte1 = Ascb(Midb(lsGroupBinary, 1, 1)): SaveBits1 = Byte1 And 3
Byte2 = Ascb(Midb(lsGroupBinary, 2, 1)): SaveBits2 = Byte2 And 15
Byte3 = Ascb(Midb(lsGroupBinary, 3, 1))
Char1 = Midb(sBASE_64_CHARACTERS, ((Byte1 And 252) \ 4) + 1, 1)
Char2 = Midb(sBASE_64_CHARACTERS, (((Byte2 And 240) \ 16) Or (SaveBits1 * 16) And &HFF) + 1, 1)
Char3 = Midb(sBASE_64_CHARACTERS, (((Byte3 And 192) \ 64) Or (SaveBits2 * 4) And &HFF) + 1, 1)
Char4 = Midb(sBASE_64_CHARACTERS, (Byte3 And 63) + 1, 1)
lsGroup64 = Char1 & Char2 & Char3 & Char4
lsResult = lsResult & lsGroup64
Next
if M3 > 0 then
lsGroup64 = ""
lsGroupBinary = Midb(asContents, len2+1, 3)
Byte1 = Ascb(Midb(lsGroupBinary, 1, 1)): SaveBits1 = Byte1 And 3
Byte2 = Ascb(Midb(lsGroupBinary, 2, 1)): SaveBits2 = Byte2 And 15
Byte3 = Ascb(Midb(lsGroupBinary, 3, 1))
Char1 = Midb(sBASE_64_CHARACTERS, ((Byte1 And 252) \ 4) + 1, 1)
Char2 = Midb(sBASE_64_CHARACTERS, (((Byte2 And 240) \ 16) Or (SaveBits1 * 16) And &HFF) + 1, 1)
Char3 = Midb(sBASE_64_CHARACTERS, (((Byte3 And 192) \ 64) Or (SaveBits2 * 4) And &HFF) + 1, 1)
if M3=1 then
lsGroup64 = Char1 & Char2 & ChrB(61) & ChrB(61)
else
lsGroup64 = Char1 & Char2 & Char3 & ChrB(61)
end if
lsResult = lsResult & lsGroup64
end if
Base64encode = lsResult
End Function
Function Base64decode(asContents)
'将Base64编码字符串转换成Ansi编码的字符串
'asContents应当也是ANSI编码的字符串（二进制的字符串也可以）
Dim lsResult
Dim lnPosition
Dim lsGroup64, lsGroupBinary
Dim Char1, Char2, Char3, Char4
Dim Byte1, Byte2, Byte3
Dim M4,len1,len2
len1= Lenb(asContents)
M4 = len1 Mod 4
if len1 < 1 or M4 > 0 then
Base64decode = ""
exit Function
end if
if midb(asContents, len1, 1) = chrb(61) then m4=3
if midb(asContents, len1-1, 1) = chrb(61) then m4=2
if m4 = 0 then
len2=len1
else
len2=len1-4
end if
For lnPosition = 1 To Len2 Step 4
lsGroupBinary = ""
lsGroup64 = Midb(asContents, lnPosition, 4)
Char1 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 1, 1)) - 1
Char2 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 2, 1)) - 1
Char3 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 3, 1)) - 1
Char4 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 4, 1)) - 1
Byte1 = Chrb(((Char2 And 48) \ 16) Or (Char1 * 4) And &HFF)
Byte2 = lsGroupBinary & Chrb(((Char3 And 60) \ 4) Or (Char2 * 16) And &HFF)
Byte3 = Chrb((((Char3 And 3) * 64) And &HFF) Or (Char4 And 63))
lsGroupBinary = Byte1 & Byte2 & Byte3
lsResult = lsResult & lsGroupBinary
Next
'处理最后剩余的几个字符
if M4 > 0 then
lsGroupBinary = ""
lsGroup64 = Midb(asContents, len2+1, m4) & chrB(65) 'chr(65)=A，转换成值为0
if M4=2 then '补足4位，是为了便于计算
lsGroup64 = lsGroup64 & chrB(65)
end if
Char1 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 1, 1)) - 1
Char2 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 2, 1)) - 1
Char3 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 3, 1)) - 1
Char4 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 4, 1)) - 1
Byte1 = Chrb(((Char2 And 48) \ 16) Or (Char1 * 4) And &HFF)
Byte2 = lsGroupBinary & Chrb(((Char3 And 60) \ 4) Or (Char2 * 16) And &HFF)
Byte3 = Chrb((((Char3 And 3) * 64) And &HFF) Or (Char4 And 63))
if M4=2 then
lsGroupBinary = Byte1
elseif M4=3 then
lsGroupBinary = Byte1 & Byte2
end if
lsResult = lsResult & lsGroupBinary
end if
Base64decode = lsResult
End Function
'------------------------------------------------------------------
Function Base64EncodeStr(tpStr)
Base64EncodeStr=strAnsi2Unicode(Base64encode(strUnicode2Ansi(tpStr)))
End Function
Function Base64DecodeStr(tpStr)
Base64DecodeStr=strAnsi2Unicode(Base64decode(strUnicode2Ansi(tpStr)))
End Function
%>
<%
'可用于加密一串地址,多个字符串
A_Key=split("96,44,63,80",",") '定义密钥
'*********加密的过程*********
Function EnCrypt(m)
Dim strChar,iKeyChar,iStringChar,I
k=0
for I = 1 to Len(m)
iKeyChar =Cint(A_Key(k))
iStringChar = Asc(mid(m,I,1)) '获取字符的ASCII码值
iCryptChar = iKeyChar Xor iStringChar '进行异或运算
'对密钥进行移位运算
If k<3 Then
k=k+1
Else
k=0
End If
c = c & Chr(iCryptChar)
next
EnCrypt = c
End Function
'*********解密的过程*********
Function DeCrypt(c)
Dim strChar, iKeyChar, iStringChar, I
k=0
for I = 1 to Len(c)
iKeyChar =Cint(A_Key(k))
iStringChar = Asc(mid(c,I,1))
iDeCryptChar = iKeyChar Xor iStringChar '进行异或运算
'对密钥进行移位运算
If k<3 Then
k=k+1
Else
k=0
End If
strDecrypted = strDecrypted & Chr(iDeCryptChar)
next
DeCrypt = strDecrypted
End Function
'中文 可以！但要将所有 Asc() 函数换成 AscW() 函数, Chr() 函数换成 ChrW() 函数！
%>
<%
'-----------------------------------------------------------------
'简单加密解密
'加密：
'适用于任何字符，包括空格和url冲突的"&""?""%"汉字等符号
'简单加密，可以改造成移位加密，比如每个字符asc码值增加或减少一个数字
'可以改造成移位随机加密。
'比如每个字符前有一个随机数字，表示该字符asc码值增加或减少这个随机数字
'-----------------------------------------------------------------
Function Smp_Encode(x) '加密
for i=1 to len(x)
TempNum=hex(asc(mid(x,i,1)))
if len(TempNum)=4 then
Smp_Encode=Smp_Encode & cstr(TempNum)
else
Smp_Encode=Smp_Encode & "00" & cstr(TempNum)
end if
next
End Function
Function Smp_Decode(x) '解密
for i=1 to len(x) step 4
Smp_Decode=Smp_Decode & chr(int("&H" & mid(x,i,4)))
next
End Function
%>
<%
Function S_Encode(str) '加密字符串
'str = EnCrypt(str)
'str = Base64EncodeStr(str)
str = Smp_Encode(str)
S_Encode = str
End Function
Function S_Decode(str) '解密字符串
'str = DeCrypt(str)
'str = Base64DecodeStr(str)
str = Smp_Decode(str)
S_Decode = str
End Function
%>
<%
Dim theFStr,theEStr,theLStr,IfReal
theFStr = "#$%&'()*+,.-_/:;<=>?@[\\]^`{|}~%中文" '原始字符串
theEStr = Str_Encode(theFStr) '加密字符串
theLStr = Str_Decode(theEStr) '还原字符串
If theFStr=theLStr Then
IfReal = True
Else
IfReal = False
End If
Response.Write "加密前为:"& theFStr &"<BR>"&VbCrlf
Response.Write "加密前字符长度:"& Len(theFStr) &"<BR><BR>"
Response.Write "加密后为:"& theEStr &"<BR>"&VbCrlf
Response.Write "加密后的字符长度:"& Len(theEStr) &"<BR><BR>"
Response.Write "解密(还原)后为:" & theLStr &"<BR>"&VbCrlf
Response.Write "前后字符是否相等:" & IfReal &"<BR>"&VbCrlf
%>
9. VB文本加密解密
刚好以前写过一篇文章，提取了一部分
对敏感的数据进行加密是必要的，如用户的密码的加密。在要对数据进行加密前得确定要用何种加密方式，加密分类有很多种，从可逆角度可分为可逆和不可逆，从加密算法可分为秘密密钥算法、公开密钥算法（用于加密、数据签名和密钥管理）以及单向散列函数等。md5加密是不可逆的，md5加密的具体实现又分为许多种。
加密为什么要采用不可逆？举个例子，当你输入的密码进行加密的密文被截取，那他也要把密文解密成原文，这时由于不可逆，那他要破解密码的难度就提高，除非他可以越过加密那一步直接提供密文，这样就达到安全的目的。每当我们忘记密码进行找回密码，大多数网站要求我们输入新的密码而不是直接告诉我们原来的密码，这是由于不可逆造成的，但这又不是坏处，为什么这么说？如果在找回密码时能够知道原来的密码，那么卧底就不用修改密码来监控所有人，而所有人又不知情。但并不是所有网站都采用不可逆的算法，笔者在某网站注册过用户，有一段没登录过，那网站就会给笔者一份提醒邮件，而这提醒邮件又显示着笔者的密码，这很可能是这个网站采用的不是不可逆的算法。
今天为一个网友实现了一个简易的自定义加密方式，使用的是Visual Basic 6.0。关键代码如下：
Dim decode As String, encode As String, oldString As String, newString As String
Dim i As Integer
decode = "1234567890" '加密原文对照字符，不应该出错相同的字符
encode = "eoSDriKjsd" '加密成密文的对照字符，字符个数不能少于decode，否则极易造成出错
oldString = "87232" '待加密的字符串，所有字符都必需能够在decode里找到对应位置
newString = "" '存放加密后的字符串
For i = 1 To Len(oldString)
newString = newString + Mid$(encode, Instr(decode, Mid$(oldString, i, 1)), 1)
Next i
Print "原文："; oldString
Print "密文："; newString
decode和encode的值可以根据需要设置，oldString可以由文框输入，如果encode里的字符俩俩不相同，那么只需调换decode和encode的值，就可以实现解密，否则加密后的密文为不可逆。
当然，在实际的应用种应增加加密的算法复杂度，让密文不至于被人轻而易举破解。更多的加密知识请参考相关文档。
希望回答对你有帮助
10. VB中md5命令函数是什么
下面是完整的类，可以设置任意密码
'DES及md5加密解密----添加引用中添加对system.web的引用。
Imports System.Security.Cryptography
Imports System
Imports System.Text
Imports System.Web
''' <summary>
''' DES加密类
''' </summary>
''' <remarks></remarks>
Public Class DESEncrypt
Public Sub DESEncrypt()
End Sub
Public Shared Function Encrypt(ByVal Text As String) As String
Return Encrypt(Text, "12345678")
End Function
Public Shared Function Encrypt(ByVal Text As String, ByVal sKey As String) As String
Dim des As New DESCryptoServiceProvider()
Dim inputByteArray As Byte()
inputByteArray = Encoding.Default.GetBytes(Text)
des.Key = ASCIIEncoding.ASCII.GetBytes(System.Web.Security.FormsAuthentication.(sKey, "md5").Substring(0, 8))
des.IV = ASCIIEncoding.ASCII.GetBytes(System.Web.Security.FormsAuthentication.(sKey, "md5").Substring(0, 8))
Dim ms As New System.IO.MemoryStream()
Dim cs As New CryptoStream(ms, des.CreateEncryptor(), CryptoStreamMode.Write)
cs.Write(inputByteArray, 0, inputByteArray.Length)
cs.FlushFinalBlock()
Dim ret As New StringBuilder()
Dim b As Byte
For Each b In ms.ToArray()
ret.AppendFormat("{0:X2}", b)
Next
Return ret.ToString()
End Function
Public Shared Function Decrypt(ByVal Text As String) As String
Return Decrypt(Text, "12345678")
End Function
Public Shared Function Decrypt(ByVal Text As String, ByVal sKey As String) As String
Dim des As New DESCryptoServiceProvider()
Dim len As Integer
len = Text.Length / 2
Dim inputByteArray(len - 1) As Byte
Dim x, i As Integer
For x = 0 To len - 1
i = Convert.ToInt32(Text.Substring(x * 2, 2), 16)
inputByteArray(x) = CType(i, Byte)
Next
des.Key = ASCIIEncoding.ASCII.GetBytes(System.Web.Security.FormsAuthentication.(sKey, "md5").Substring(0, 8))
des.IV = ASCIIEncoding.ASCII.GetBytes(System.Web.Security.FormsAuthentication.(sKey, "md5").Substring(0, 8))
Dim ms As New System.IO.MemoryStream()
Dim cs As New CryptoStream(ms, des.CreateDecryptor(), CryptoStreamMode.Write)
cs.Write(inputByteArray, 0, inputByteArray.Length)
cs.FlushFinalBlock()
Return Encoding.Default.GetString(ms.ToArray())
End Function
End Class
'以下是调用方法
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click '加密
Dim str_Encrypt As String = DESEncrypt.Encrypt("你要加密的文本，可以是任意长度", "密码，可以很长，如果省略这个参数就是默认的12345678")
End Sub
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click '解密
Dim str_Decrypt As String = DESEncrypt.Decrypt("你要解密的文本, 可以是任意长度", "加密时用到的密码，如果省略这个参数就是默认的12345678")
End Sub