纸牌游戏编程
A. 扑克牌游戏比大小用C++编程，求答案，求大神！
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<windows.h>
usingnamespacestd;
intsum=0;
intpc_win=0;
intman_win=0;
voidswap(inta[],intm,intn,chars[]){//交换两个牌（用于洗牌）
intc=a[m];
a[m]=a[n];
a[n]=c;
chard=s[m];
s[m]=s[n];
s[n]=d;
}
voidxipai(inta[],intn,chars[]){//洗牌
inti=1,j=1;
for(i=0;i<n;i++){
do{
j=rand()%52;
}while(j==i);
swap(a,i,j,s);
}
}
voidfapai(inta[],intb[],intc[],chars[],charps[],charms[]){//发牌
inti=0,m=25,n=25;
for(i=0;i<52;i++){
if(i%2){
b[m]=a[i];
ps[m--]=s[i];
}
else{
ms[n]=s[i];
c[n--]=a[i];
}
}
}
voidplay(intb[],intc[],char*m[],charps[],charms[]){//游戏开始
inta1=0,a2=0;
inti=0;
for(;i<26;i++){
if(b[i]==c[i])
cout<<"电脑出的牌是"<<ps[i]<<m[b[i]]<<", 你出的牌是"<<ms[i]<<m[c[i]]<<endl;
elseif(b[i]>c[i]){
a1++;
cout<<"电脑出的牌是"<<ps[i]<<m[b[i]]<<", 你出的牌是"<<ms[i]<<m[c[i]]<<endl;
}else{
a2++;
cout<<"电脑出的牌是"<<ps[i]<<m[b[i]]<<", 你出的牌是"<<ms[i]<<m[c[i]]<<endl;
}
Sleep(300);
}
sum++;
if(a1==a2)
cout<<" 平局了"<<endl;
if(a1>a2){
pc_win++;
cout<<" 可惜你输了"<<endl;
}
if(a1<a2){
man_win++;
cout<<" 恭喜你赢了"<<endl;
}
}
voidshow(inta[],char*m[],charms[]){
inti=0;
cout<<"你有的牌和顺序是:"<<endl;
for(i=0;i<26;i++)
cout<<ms[i]<<m[a[i]]<<'';
cout<<endl;
}
voidshowscore(){
if(sum==0){
cout<<"还没比呢，着什么急啊"<<endl;
return;
}
printf("现在的大比分是：%d:%d",man_win,pc_win);
if(man_win>pc_win)
cout<<"你领先呢，恭喜"<<endl;
elseif(man_win<pc_win)
cout<<"你落后呢，加油"<<endl;
elseif(man_win==pc_win)
cout<<"战局很焦灼，再接再厉"<<endl;
}
voidstart(inta[],intb[],intc[],char*m[],chars[],charps[],charms[]){
chari=0;
srand((unsignedint)time(0));
cout<<"欢迎来到比大小游戏中，请选择： 1、开始游戏2、显示比分3、退出游戏"<<endl;
while(i=getch()){
switch(i){
case'1':
xipai(a,52,s);
fapai(a,b,c,s,ps,ms);
show(c,m,ms);
play(b,c,m,ps,ms);
break;
case'2':
showscore();
break;
case'3':
return;
}
cout<<" 欢迎来到比大小游戏中，请选择： 1、开始游戏2、显示比分3、退出游戏"<<endl;
}
}
intmain(){
inta[60]={0},pc[30]={0},man[30]={0};
chars[60]={0},pc_s[30]={0},man_s[30]={0};
char*m[14]={"0","1","2","3","4","5","6","7","8","9","10","J","Q","K"};
inti;
for(i=0;i<13;i++){
s[i]=3;
s[i+13]=4;
s[i+26]=5;
s[i+39]=6;
a[i]=a[i+13]=a[i+26]=a[i+39]=i+1;
}
start(a,pc,man,m,s,pc_s,man_s);
cout<<"欢迎再次来玩本游戏"<<endl;
return0;
}
B. 扑克牌游戏软件开发
直接回答问题：
这边报价是5.5万左右，开发周期1.5个月左右，欢迎题主考察公司！
C. c语言程序设计课程设计扑克牌游戏，怎么做
#include<conio.h>
#include<time.h>
#include<stdio.h>
#include<stdlib.h>
int jisuan(int);
int comptotal;
char s1[]="A234567890JQK";
//char s2[4][5]={"红桃","黑桃","草花","方块"};
char s2[4]={3,4,5,6};
int poke[52];
int ch;
int win=0;
int computer[5],user[5];
int usertotal;
int users;
int k;
int main()
{ void xipai(int poke[]);
void ai();
int i,j;
////////////////////////////////////////////////////////上面是变量和声明
printf("\n这是简单的廿一点游戏:\n");
for(i=0;i<52;i++)
{
if(i%13==0)putchar('\n');
poke[i]=i;
printf("%c%c%c ",s2[i/13],s1[i%13]=='0'?'1':' ',s1[i%13]);
}
putchar('\n');
/////////////////////////////////////////////////////////主代码
k=0;
xipai(poke);
while(ch!=27)
{ comptotal=0;
usertotal=0;
if(k>=42)
{
printf("\n剩余牌数不足十张,重新洗牌");
xipai(poke);
k=0;
}
printf("\n\n\n\n\n\n\n\n新局开始:\n");
printf("现在共有牌%2d张\n",52-k);
if(win==0)
{
computer[0]=k++;
user[0]=k++;
printf("\n电脑做庄,要牌:");
ai();
}
else
{
printf("\n玩家做庄,要牌:\n\t回车要牌\n\t空格过牌");
user[0]=k++;
computer[0]=k++;
}
printf("\n玩家开始要牌:\n");
usertotal=jisuan(poke[user[0]]);
printf("%c%c%c 共%2d点\t",s2[poke[user[0]]/13],s1[poke[user[0]]%13]=='0'?'1':' ',s1[poke[user[0]]%13],usertotal);
users=0;
ch=1;
while(ch!=32&&users<4)
{
ch=getch();
switch(ch)
{
case 27:
goto end;
break;
case 32:
break;
case 13:
user[++users]=k;
usertotal+=jisuan(poke[user[users]]);
printf("\b\b\b\b\b\b\b\b\b%c%c%c 共%2d点\t",s2[poke[k]/13],s1[poke[k]%13]=='0'?'1':' ',s1[poke[k]%13],usertotal);
k++;
if(usertotal>=21)ch=32;
break;
default:
break;
}
}
if(win==1)
{
printf("\n电脑开始要牌:\n");
ai();
}
printf("\n\n\n玩家的点数是%2d",usertotal);
printf("\n电脑的点数是%2d",comptotal);
printf("\n\n本局结算:");
if(comptotal>21&&usertotal<=21)
{
printf("\n\n电脑爆牌了");
win=1;
printf("\n恭喜,你赢了");
}
if(usertotal>21&&comptotal<=21)
{
printf("\n\n你爆牌了");
printf("\n下次小心点");
win=0;
}
if(usertotal>21&&comptotal>21)
{
printf("\n\n你们两个，怎么都这么不小心啊,都撑死了还要吗");
}
if(usertotal<=21&&comptotal<=21)
{
if(usertotal>comptotal)
{
win=1;
printf("\n\n不错，你赢了");
}
else if(usertotal<comptotal)
{
win=0;
printf("\n\n撑死胆大的，饿死胆小的，没胆子，输了吧");
}
else
printf("\n\n平了，算你走运");
}
getch();
}
end:
return 0;
}
void xipai(int poke[])
{
int y,tmp,i,j;
for(j=0;j<7;j++)
for(i=0;i<52;i++)
{
srand(time(0));
y=rand()%10;
tmp=poke[i];
poke[i]=poke[(y*i*i)%52];
poke[(y*i*i)%52]=tmp;
}
}
///////////////////////////////////////////////子函数
void ai()
{
int i;
comptotal=jisuan(poke[computer[0]]);
printf("\n%c%c%c 共%2d点\t",s2[poke[computer[0]]/13],s1[poke[computer[0]]%13]=='0'?'1':' ',s1[poke[computer[0]]%13],comptotal);
for(i=0;i<4;i++)
{
if(comptotal<17)
{
computer[i+1]=k++;
comptotal+=jisuan(poke[computer[i+1]]);
printf("\b\b\b\b\b\b\b\b\b%c%c%c 共%2d点\t",s2[poke[computer[i+1]]/13],s1[poke[computer[i+1]]%13]=='0'?'1':' ',s1[poke[computer[i+1]]%13],comptotal);
}
}
}
int jisuan(int i)
{int dian;
switch(i%13)
{
case 0:
case 10:
case 11:
case 12:
dian=1;
break;
default:
dian=i%13+1;
}
return dian;
}
D. 纸牌游戏:十点半c语言编程
参考下面代码
#include<stdio.h>
struct card{
int num;//
bool ex;//真为正面，假为反面
};
void show(struct card a[],int n){// 显示正面朝上的纸牌
int i = 0,j = 0;
printf("第%02d次:",n);
for(i = 0;i < 52;i ++){
if(a[i].ex){
j++;
printf("%02d ",a[i].num);
if(j == 23){
printf("\n ");
}
}
}
printf("\n\n");
}
void main()
{
int i,j;
struct card a[52];
for(i = 0;i < 52;i ++){
a[i].num = i+1;
a[i].ex = true;
}//初始化纸牌
for(i = 2;i < 53;i ++){
for(j = 0;j < 52;j ++){
if((j+1)%i == 0)
a[j].ex = !a[j].ex;
}
show(a,i-1);
}
E. c++扑克牌游戏编程
个人建议：学习c、c++语言最好是自己动手去做，在学校的时间是宝贵的，要想做个好程序员就得在学校打好基础，这样工作才会有保障，这个题目应该是你的作业部分吧，尽量自己去完成吧，完成后你会发现你有很大的收获，不仅仅是知识上的，更多的是学习乐趣和方法，作为一个过来人和你分享下个人经验，祝你学习进步，呵呵，如果是中间出现困难了，可以和大家一起交流
F. c语言程序设计扑克牌游戏
定义一个结构类型表示一张牌，结构包含3个成员，第一个成员char：取值2，3~K，A表示牌名字，第二个成员int:取值2~14表示牌真实大小。第三个成员:结构链表指针。
写一个初始化函数，定义52大小的结构数组，成员值初值分别和牌对应，遍历数组并将每个元素的链表指针依次指向下一个元素地址。这样得到一个初始链表。（相当于一盒新牌）
所有涉及随机数都用rand函数，洗牌分四份就是循环取随机数m=1~n，n是随循环自减，初值52，直到n变成0。每随一次循环就从初始链表中遍历取出对应第m个节点，并从初始链表中将这个节点断开（既前一个节点指针直接指向后一个节点指针）。每取13张就组成一个新的链表。这样获得4个新链表分别表示4个玩家。
最后出牌就是分别遍历自己的链表，利用循环取牌比较结构数值大小。（取出的牌要从链表断开和上面一样，你把取出节点写成独立函数就能反复使用）。
G. 用Qt编程纸牌游戏中的纸牌用什么构件啊
QGraphicsItem,QGraphicsView,QGraphicsScene.
很难的,但是很灵活.
祝好运.
H. 求C++纸牌（52张）比大小游戏编程设计
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
struct card
{ char suit[2];
char face[3];
};
typedef struct card CARD;
void initcard(CARD deck[],char s[][2],char f[][3]);
void shuffle(CARD deck[]);
void print(CARD deck[]);
I. C语言编程，纸牌游戏
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <dos.h>
#include <graphics.h>
#include <conio.h>
#define ESC 0x1b
struct card
{
char color;
int number;
int signin;
}a[52]={{3,2,1},{3,3,1},{3,4,1},{3,5,1},{3,6,1},{3,7,1},{3,8,1},{3,9,1},{3,10,1},{3,74,1},{3,81,1},{3,75,1},{3,65,1},
{4,2,1},{4,3,1},{4,4,1},{4,5,1},{4,6,1},{4,7,1},{4,8,1},{4,9,1},{4,10,1},{4,74,1},{4,81,1},{4,75,1},{4,65,1},
{5,2,1},{5,3,1},{5,4,1},{5,5,1},{5,6,1},{5,7,1},{5,8,1},{5,9,1},{5,10,1},{5,74,1},{5,81,1},{5,75,1},{5,65,1},
{6,2,1},{6,3,1},{6,4,1},{6,5,1},{6,6,1},{6,7,1},{6,8,1},{6,9,1},{6,10,1},{6,74,1},{6,81,1},{6,75,1},{6,65,1}},b[52];
char s[10];
int d[52];
fan(int n)
{
if(a[n].signin==0)
a[n].signin=1;
else a[n].signin=0;
return;
}
suiji()
{
int t=0,j,i=0,struction;
for(i=0;i<=51;i++)
d[i]=-1;
i=0;
randomize();
while(i<52)
{
struction=random(52);
for(j=0;j<i;j++)
{
if(d[j]==struction)
{
t=1;
break;
}
}
if(t==0)
{
d[i]=struction;
i++;
}
else t=0;
}
return;
}
card(int n)
{
int y,x=n%13,x1=d[n]%13,y1;
char s1[2],r[2];
y=(n-x)/13;
setcolor(15);
line(49*x,80*y+42,49*x,80*y+117);
line(49*x+47,80*y+42,49*x+47,80*y+117);
line(49*x,80*y+42,49*x+47,80*y+42);
line(49*x,80*y+117,49*x+47,80*y+117);
for(y1=1;y1<75;y1++)
{
setcolor(15);
line(49*x+1,80*y+y1+42,49*x+45,80*y+y1+42);
}
if(a[n].signin==1)
{
setcolor(1);
if(a[d[n]].color==3||a[d[n]].color==4)
setcolor(RED);
sprintf(s1,"%c",a[d[n]].color);
outtextxy(49*x+3,80*y+45,s1);
if(x1<9)
sprintf(r,"%d",a[d[n]].number);
else sprintf(r,"%c",a[d[n]].number);
outtextxy(49*x+3,80*y+54,r);
}
else against(n);
setcolor(WHITE);
return;
}
against(int n)
{
int y,y1,x=n%13;
y=(n-x)/13;
for(y1=1;y1<75;y1++)
{
setcolor(BLUE);
line(49*x+1,80*y+y1+42,49*x+45,80*y+y1+42);
}
setcolor(15);
return;
}
draw(int n,int m)
{
int i4;
setcolor(YELLOW);
sprintf(s,"Base: %d",n);
outtextxy(150,420,s);
if(d[m-1]%13<9&&d[m-1]%13>=0)
sprintf(s,"Card: %c %d",a[d[m-1]].color,a[d[m-1]].number);
else sprintf(s,"Card: %c %c",a[d[m-1]].color,a[d[m-1]].number);
outtextxy(150,430,s);
setcolor(15);
for(i4=0;i4<52;i4++)
{
card(i4);
}
return;
}
frame(int n)
{
int y,x=n%13;
y=(n-x)/13;
setcolor(RED);
line(49*x,80*y+42,49*x,80*y+117);
line(49*x+47,80*y+42,49*x+47,80*y+117);
line(49*x,80*y+42,49*x+47,80*y+42);
line(49*x,80*y+117,49*x+47,80*y+117);
setcolor(15);
return;
}
huatu(int i,int j)
{
int n,m,i1=i,b,b2,j1=j,sign=0,tar=0,i2=2,k=1,p,sign1=0;
char u='',u1='',c[7][8],chh;
setbkcolor(3);
while(1)
{
loop:
sprintf(c[0],"File");
sprintf(c[1],"Option");
sprintf(c[2],"Help");
sprintf(c[3],"New");
sprintf(c[4],"Exit");
sprintf(c[5],"Auto");
sprintf(c[6],"Manual");
while(i2<=52)
{
k=1;
while(i2*k<=52)
{
setcolor(9);
for(n=0;n<=18;n++)
line(0,n,639,n);
setcolor(15);
outtextxy(290,10,"Card Game");
setcolor(YELLOW);
for(n=19;n<=40;n++)
line(0,n,639,n);
for(m=0;m<=2;m++)
{
setcolor(0);
line(58*m+3,22,58*m+3,38);
line(58*m+3,38,58*m+58,38);
line(58*m+58,22,58*m+58,38);
line(58*m+3,22,58*m+58,22);
outtextxy(8+58*m,27,c[m]);
if(m==i1)
{
setcolor(0);
for(n=0;n<=16;n++)
line(58*m+3,22+n,58*m+58,22+n);
setcolor(YELLOW);
outtextxy(8+58*m,27,c[m]);
}
if(kbhit())
{
chh=getch();
if(chh==0x1b)
{
u='';
u1='';
goto loop;
}
}
}
if(u!='N')
{
sign1=1;
break;
}
if(u=='N')
{
if(u1!='A'&&u1!='M')
{
p=i2*k;
draw(i2,p);
sign1=1;
break;
}
if(u1=='A'||u1=='M')
{
p=i2*k;
draw(i2,p);
sign1=0;
fan(i2*k-1);
frame(i2*k-1);
if(u1=='M')
{
outtextxy(150,440,"Press any key to continue!");
getch();
}
cleardevice();
k++;
}
}
}
if(sign1==1)break;
i2++;
}
if(i2>=52)
{
setcolor(9);
for(n=0;n<=18;n++)
line(0,n,639,n);
setcolor(15);
outtextxy(290,10,"Card Game");
setcolor(YELLOW);
for(n=19;n<=40;n++)
line(0,n,639,n);
outtextxy(150,420,"Press any key to continue!");
for(m=0;m<=2;m++)
{
setcolor(0);
line(58*m+3,22,58*m+3,38);
line(58*m+3,38,58*m+58,38);
line(58*m+58,22,58*m+58,38);
line(58*m+3,22,58*m+58,22);
outtextxy(8+58*m,27,c[m]);
if(m==i1)
{
for(n=0;n<=16;n++)
line(58*m+3,22+n,58*m+58,22+n);
setcolor(YELLOW);
outtextxy(8+58*m,27,c[m]);
}
} /*打印一级菜单*/
getch();
cleardevice();
setcolor(9);
for(n=0;n<=18;n++)
line(0,n,639,n);
setcolor(15);
outtextxy(290,10,"Card Game");
setcolor(YELLOW);
for(n=19;n<=40;n++)
line(0,n,639,n);
for(m=0;m<=2;m++)
{
setcolor(0);
line(58*m+3,22,58*m+3,38);
line(58*m+3,38,58*m+58,38);
line(58*m+58,22,58*m+58,38);
line(58*m+3,22,58*m+58,22);
if(m==i1)
{
for(n=0;n<=16;n++)
line(58*m+3,22+n,58*m+58,22+n);
setcolor(YELLOW);
}
outtextxy(8+58*m,27,c[m]);
}
draw(52,52);
}
if(u1=='M'||u1=='A')
{
u1='';
u='';
}
b=getch();
while(1)
{
if(b==100)
{
i1=(i1+1)%3;
break;
}
if(b==97)
{
if(i1==0)
{
i1=2;
break;
}
else
{
i1=i1-1;
break;
}
}
/* if(b==0x1b)
{
closegraph();
exit(1);
} */
if(b==13)
{
while(1)
{
if(i1!=2)
{
if(sign!=1)
{
setcolor(YELLOW);
for(m=1;m<=2;m++)
{
line(58*i1+3,38+15*(m-1),58*i1+3,53+15*(m-1));
line(58*i1+3,53+15*(m-1),58*i1+58,53+15*(m-1));
line(58*i1+58,38+15*(m-1),58*i1+58,53+15*(m-1));
line(58*i1+3,38+15*(m-1),58*i1+58,38+15*(m-1));
setcolor(3);
for(n=0;n<=13;n++)
{
line(58*i1+4,39+15*(m-1)+n,58*i1+57,39+15*(m-1)+n);
}
if(m==j1+1)
{
setcolor(3);
for(n=0;n<=13;n++)
{
line(58*i1+4,39+15*(tar)+n,58*i1+57,39+15*(tar)+n);
}
setcolor(BLUE);
for(n=0;n<=13;n++)
{
line(58*i1+4,39+15*(j1)+n,58*i1+57,39+15*(j1)+n);
}
tar=j1;
}
setcolor(YELLOW);
}
setcolor(YELLOW);
if(i1==0)
{
outtextxy(8+58*i1,43,c[i1+3]);
outtextxy(8+58*i1,58,c[i1+4]);
}
else
{
outtextxy(8+58*i1,43,c[i1+4]);
outtextxy(8+58*i1,58,c[i1+5]);
}
}
if(sign==1)break;
setcolor(YELLOW);
while(1)
{
b2=getch();
if(b2==115)
{
j1=(j1+1)%2;
break;
}
if(b2==119)
{
if(j1==1)
{
j1=0; break;
}
if(j1==0)
{
j1=1; break;
}
}
if(b2==0x1b)
{
sign=1;
j1=0;
break;
}
if(b2==13)
{
if(i1==0&&j1==1)
{
closegraph();
exit(1);
}
if(i1==0&&j1==0)
{
u='N';
suiji();
for(n=0;n<52;n++)
{
a[n].signin=1;
}
n=0;
}
if(i1==1&&j1==0)
{
u1='A';
if(u!='N') u1='';
}
if(i1==1&&j1==1)
{
u1='M';
if(u!='N') u1='';
}
sign=1;
j1=0;
break;
}
else continue;
}
}
else
{
sign=1;
outtextxy(100,100,"Copyright");
circle(180,104,5);
outtextxy(177,101,"C");
getch();
break;
}
}
}
else break;
if(sign==1)
{
sign=0;
break;
}
}
cleardevice();
i2=2;
k=1;
}
}
main()
{
int k,gm=2,gd=9;
initgraph(&gd,&gm,"");
huatu(0,0);
getch();
}
J. 24点纸牌游戏的开发 python 各路大神我需要帮助
很久之前自己写的了，用的就是高级一点的穷举，还挺快的。
附带一个gui
求给分啊
两个文件，cui负责算数gui是界面，亲测可运行的
**************************************cui_24point.py
__author__ = 'Administrator'
add = lambda a,b:a+b
minus = lambda a,b:a-b
mul = lambda a,b:a*b
div = lambda a,b:a/b
caldict = {add:"+", minus:"-", mul:"*", div:"/"}
sortlist = [[a,b,c,d] for a in range(4) for b in range(4) for c in range(4) for d in range(4) if a != b != c != d and a != c and b != d and a != d]
class leaf:
def __init__(self, numlist, layer1, layer2, layer3, ans):
self.numlist = map(lambda a:float(a), numlist)
self.layer1 = layer1
self.layer2 = layer2
self.layer3 = layer3
self.ans = ans
def __str__(self):
return "((%s%s%s)%s%s)%s%s=%s" %(self.numlist[0], caldict[self.layer1], self.numlist[1], caldict[self.layer2], self.numlist[2], caldict[self.layer3], self.numlist[3] ,self.ans)
def tree(numlist):
layer1 = "Null"
layer2 = "Null"
layer3 = "Null"
for c1 in [add, minus, mul, div]:
layer1 = c1
for c2 in [add, minus, mul, div]:
layer2 = c2
for c3 in [add, minus, mul, div]:
layer3 = c3
if c3(c2(c1(numlist[0], numlist[1]), numlist[2]), numlist[3]) == 24:
return leaf(numlist, layer1, layer2, layer3, 24)
class Turn():
def __init__(self, numlist):
if len(numlist) == 4:
self.numlist = numlist
def calculate(self):
anslist = []
for i in sortlist:
templist = [self.numlist[i[0]], self.numlist[i[1]], self.numlist[i[2]], self.numlist[i[3]]]
anslist.append(tree(templist))
return anslist
def calc(templist):
ans = Turn(templist).calculate()
ans = [i for i in ans if i != None]
for i in ans:
print i
return ans
if __name__ == "__main__":
templist = []
for i in range(4):
templist.append(int(raw_input("Input No.%s number \n" %i)))
calc(templist)
*****************************************gui.py
# -*- coding: -UTF-8 -*-
__author__ = 'Administrator'
from Tkinter import *
import cui_24point
root = Tk()
root.geometry("800x400+400+400")
root.title("24点计算程式")
numlist = []
ansVar = StringVar()
def initvariable():
for i in range(4):
numlist.append(StringVar())
def drawframe():
entryframe = Frame(root, width = 300, height = 100)
for i in range(4):
Label(entryframe, text = str(i + 1)).grid(row = 1, column = i)
Entry(entryframe, textvariable = numlist[i]).grid(row = 2, column = i)
entryframe.pack()
ansframe = Frame(root, width = 100, height = 66)
anslistbox = Listbox(ansframe, width = 50, listvariable = ansVar)
ansscrollbar = Scrollbar(ansframe, command = anslistbox.yview)
anslistbox.configure(yscrollcommand = ansscrollbar.set)
anslistbox.pack(side = RIGHT)
ansscrollbar.pack(side = LEFT, fill = Y)
ansframe.pack()
def calculate():
templist = map(lambda i:float(i.get()), numlist)
for i in cui_24point.calc(templist):
anslistbox.insert(END, i)
anslistbox.insert(END, "********************")
Button(text = "计算", command = calculate).pack()
initvariable()
drawframe()