编程买票问题

Ⅰ c语言程序设计 编写程序计算飞机票款.输入舱位代码和购票数量,输出总票款

#include<stdio.h>
intmain(void)
{
	intn;
	floatf,c,y,i;
	charg;
	printf("请输入F舱、C舱和Y舱的公布价;
");
	scanf("%f%f%f",&f,&c,&y);
	getchar();
	printf("请输入仓位代码和购票数量;
");
	scanf("%c%d",&g,&n);
	switch(g)
	{
		case'B':i=y*0.9*n;break;
		case'H':i=y*0.85*n;break;
		case'K':i=y*0.8*n;break;
		case'L':i=y*0.75*n;break;
		case'M':i=y*0.7*n;break;
		case'N':i=y*0.65*n;break;
		case'Q':i=y*0.6*n;break;
		case'T':i=y*0.55*n;break;
		case'X':i=y*0.5*n;break;
	}
	printf("%.2f
",i);
}

Ⅱ 问一个python编程题，while循环买票

##注意：最左边每个=表示一个空格
while True:
====age = input('你的年龄是： ')
====if age == 'quit':
========print('结束程序')
========break
====else:
========try:
============age=int(age)
============if age<3:
================print('你可以免费入场')
============elif 3<=age<=12:
================print('票价十块钱')
============else:
================print('票价15块钱')
========exception:
============print('重新输入')

Ⅲ c语言编程，购买车票, 乘1-4站3元/位;5-9站4元/位,9站5元一位,求应付款

#include <stdio.h>
int pay(int n);
int main(){
int n;
printf("请输入乘车站数：\n");
scanf("%d",&n);
printf("需付款%d元\n",pay(n));
return 0;
}

int pay(int n){
if(n>=1 && n<=4){
return 3;
}else if(n>=5 && n<=9){
return 4;
}else if(n==9){
return 5;
}else{
return 999;//输入有误
}
}