aardio可以反編譯嗎

A. aardio 編寫的程序可以反編譯么

我的外部代碼是這么寫的:
dmhy = function(htmlCode){
var getUrl = //</topics/view/>[^\>]+<\.html>
var getTr = //<\<tr class=\">[^<]+?<\<td width>.+?<\</tr\>>
var getTitle = //<html\"><[^>]*?>\>(.+?)<\</a\>>
var delSpan = //<\<span class=\"keyword\"\>>|<\</span\>>
var getSize = //<center\"\>>([\d\.]+?\a+?)<\</td\>>
var href,trHtml,title,size,savePath;
for k in ..string.gmatch( htmlCode,getTr) {
if(k==""||k==null){
continue ;
}
k=..string.fromto(k);
href = ..string.match(k,getUrl);
href = "https://share.dmhy.org" ++ href;
title = ..string.match(k,getTitle);
title = ..string.replace(title,delSpan,"");
title = ..string.trim(title);
size = ..string.match(k,getSize);

trHtml = ..string.concat(trHtml,"<tr><td class='name'>",title,"</td><td class='size'>",size,"</td><td class='bt_state'><img class='td-img' thref='",href,"' src='/res/image/download.PNG'></td></tr>");
}
return trHtml;
}
調用時這么寫的
var f,err = loadcode("/config/filterHtml.aau");
if(f){
var trHtml =f(htmlCode);
}
沒有報任何錯誤,但 trHtml = null
請問應該怎麼做?

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