servlet跨域訪問
① 使用jquery跨域訪問servlet,那不到數據,但是在瀏覽器看請求記錄,裡面是有返回參數的
JQuery跨域問題要用Jsonp
http://www.cnblogs.com/JerryTian/p/4194900.html
這有詳細的講解
② java跨域問題
跨域問題一般都在後台程序解決，將自己的程序通過配置文件或者代碼將其允許跨域，
在有跨域安全的時候，所有前端post請求時，會發送一個與其請求名字一樣的OPTIONS
此請求沒有任何參數，此機制為post不知道是否有許可權請求介面，發送了一個探知請求，探知
請求確認後，允許訪問後調用正常Post介面。 不允許就會出現你現在的問題跨域異常。
萌新，java是開源的，比NET好多了，多看看底層
③ jsp跨域怎麼調用servlet
跨域策略兩種方式：
1：使用jsonp
2：使用cors
如果servlet返回jsop數據，就可以使用jsonp
參考代碼：
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
request.setCharacterEncoding("UTF-8");
response.setCharacterEncoding("UTF-8");
String callback=request.getParameter("callback");
// 調用業務邏輯組件獲得全部用戶數據
List<User> users = UserBiz.select();
JSONArray jsonArr = new JSONArray(users);
if (callback!=null){
response.setContentType("text/javascript; charset=UTF-8");
response.getWriter().println(callback+"("+jsonArr.toString()+");");
}else{
response.setContentType("text/html; charset=UTF-8");
response.getWriter().println(jsonArr.toString());
}
}
④ 如何用servlet訪問別人的url
我也有同樣的問題，我需要自己寫一個servlet，去跨域訪問別人伺服器上的數據，不知道你是否知道解決方法，知道的話煩請告知一下，我也想學習
⑤ servlet可以結合CROS實現ajax跨域訪問嗎如何做
如果就是servlet的話，那簡簡單單一個filter就能搞定，而且已經有人做了，直接拿來用吧：cors-filter。
如果你的問題是不理解跨域，那你得看：構建public APIs與CORS
⑥ 在Jenkins中報嚴重違規：Servlet反射跨域腳本漏洞 writer.print(value);
腳本（script）是使用一種特定的描述性語言，依據一定的格式編寫的可執行文件，又稱作宏或批處理文件。腳本是批處理文件的延伸，是一種純文本保存的程序，一般來說的計算機腳本程序是確定的一系列控制計算機進行運算操作動作的組合，在其中可以實現一定的邏輯分支等。
⑦ JS跨域訪問 通過 Spring mvc 攔截器修改返回值 HttpServletResponse
給你個例子，controller需要支持跨域的方法：
public Map<String ,Object> index(ServletResponse res){
HttpServletResponse response = (HttpServletResponse)res;
response.addHeader("Access-Control-Allow-Origin", "*");
response.addHeader("Access-Control-Allow-Methods", "POST,GET,PUT,DELETE,OPTIONS");
response.addHeader("Access-Control-Allow-Credentials", "true");
response.addHeader("Access-Control-Allow-Headers", "Content-Type,X-Requested-With,token");
response.addHeader("Access-Control-Max-Age", "600000");
//TODO
...
}
這樣就支持跨域了，但是這種方式不怎麼安全，"Access-Control-Allow-Origin"後面的*代表支持所有域名。
⑧ 怎麼解決伺服器間的跨域問題
通過設置Http Header方式允許跨域名請求
<?php
header("Access-Control-Allow-Origin: http://www.requesting-page.com");
?>
more details
browser(client) side code examples:
https://developer.mozilla.org/en-US/docs/Web/HTTP/Access_control_CORS
server side code examples:
https://developer.mozilla.org/en-US/docs/Web/HTTP/Server-Side_Access_Control
怎樣配置Apache 伺服器允許跨域名請求
How do we fix cross domain scripting issue ?
The simple solution is to allow the server to which request is being
made to server request to any domain or to a list of domains. The
important thing to remember is that the changes are to be made in the server which is serving the web service.
There are multiple ways to do it
1. You change settings in your apache』s httpd-vhosts.conf file ( I am using Apache 2.2 )
<VirtualHost *:80>
ServerAdmin [email protected]
DocumentRoot 「C:/apache-tomcat-6.0.29/webapps/myApplication」
ServerName skill-guru.com
ErrorLog 「logs/skg1-error.log」
CustomLog 「logs/skg1-access.log」 common
Header set Access-Control-Allow-Origin 「*」
<Directory 「C:/apache-tomcat-6.0.29/webapps/myApplication」>
Options -Indexes FollowSymLinks
AllowOverride AuthConfig FileInfo
Order allow,deny
Allow from all
</Directory>
JkUnmount /*.jsp ajp13
</VirtualHost>
Now after you set the value in apache server and look at the header and would see
HTTP/1.1 200 OK
Date: Mon, 01 Dec 2008 00:23:53 GMT
Server: Apache/2.0.61
Access-Control-Allow-Origin: *
Keep-Alive: timeout=2, max=100
Connection: Keep-Alive
Transfer-Encoding: chunked
Content-Type: application/xml
怎樣配置Tomcat 伺服器允許跨域名請求
If you do not plan to use Apache and for some reasons using tomcat or
any other similar web container which supports filter, here is a ready
made solution, Cors
Filter
This gives you a servlet filter which is compatible with any Java Servlet 2.5+ web container.
Installation is very simple. Add the jar to your libraries
In you web.xml
add this line
<filter>
<filter-name>CORS</filter-name>
<filter-class>com.thetransactioncompany.cors.CORSFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>CORS</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
⑨ felx 用 httpservice 另一個工程httpservlet （跨域訪問）
參考答案 溫故而知新。
⑩ spring mvc 怎麼允許跨域訪問
Controller的每一個請求返回的時候都加上Access-Control-...header，需要注意的是並不是所有的瀏覽器都支持這些header,使用之前要先了解清楚。
實現起來也很簡單那就是Interceptor,代碼如下:
ublic class AccessKeyInterceptor extends HandlerInterceptorAdapter {
private static Log log=LogFactory.getLog(AccessKeyInterceptor.class);
@Autowired
private IAccessService accessService;
private String accessKeyParameterName="accessKey";
private List<String> defaultAccessAllowedFrom;
@Override
public boolean preHandle(HttpServletRequest request, HttpServletResponse response, Object handler) throws Exception {
String accessKey=request.getParameter(accessKeyParameterName);
String referer = request.getHeader("Referer");
URL u = new URL(referer);
String host = u.getHost().toLowerCase();
if(accessKey==null){
log.error("====================================ILLEGAL ACCESS: ACCESS_KEY_MISSING!=======================");
}else{
log.debug("====================================ACCESS WITH Access KEY:"+accessKey+"====================");
IAccess access = accessService.getAccess(UserSessionUtils.getUserSession(request), accessKey);
if(access!=null){
defaultAccessAllowedFrom=access.getAccessAllowedFrom();
}else{
log.warn("======================================ACCESS KEY:"+accessKey+" DOES NOT EXIST!=================");
}
}
for(String s : defaultAccessAllowedFrom) {
if(host.matches(s)){
response.setHeader("Access-Control-Allow-Origin", referer);
break;
}
}
response.setHeader("Access-Control-Allow-Headers", "Content-Type");
response.setHeader("Access-Control-Allow-Methods", "GET");
response.setHeader("Allow", "GET");
return true;
}
public List<String> getDefaultAccessAllowedFrom() {
return defaultAccessAllowedFrom;
}
public void setDefaultAccessAllowedFrom(List<String> defaultAccessAllowedFrom) {
this.defaultAccessAllowedFrom = defaultAccessAllowedFrom;
}
public String getAccessKeyParameterName() {
return AccessKeyParameterName;
}
public void setAccessKeyParameterName(String accessKeyParameterName) {
this.AccessKeyParameterName = AccessKeyParameterName;
}
}